In Figure 1, common tangents AB and CD to the two circles with centres 0_{1}and 0_{2 }intersect at E. Prove that AB = CD.

Advertisement Remove all ads

#### Solution

Given: AB and CD are common tangents to both the circles.

To prove: AB = CD

Proof:

We know that two tangents drawn to a circle for the same exterior point are

equal.

Thus we get

AE = EC (i)

Similarly

ED = EB (ii)

AB = AE + EB (iii)

and

CD = CE + ED (iv)

AB = EC + EB from (i) and (iii)

CD = EC + EB from (ii) and (iv)

Therefore AB = CD

Hence proved.

Concept: Concept of Circle - Centre, Radius, Diameter, Arc, Sector, Chord, Segment, Semicircle, Circumference, Interior and Exterior, Concentric Circles

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads